x->3
x-3 ->0
e^(x-3) -1 ~ x-3
sin(2x-6)~ 2x-6
lim(x->3) [e^(x-3) -1]/sin(2x-6)
=lim(x->3) (x-3)/(2x-6)
=1/2
x-3 ->0
e^(x-3) -1 ~ x-3
sin(2x-6)~ 2x-6
lim(x->3) [e^(x-3) -1]/sin(2x-6)
=lim(x->3) (x-3)/(2x-6)
=1/2
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2楼2023-11-05 15:06
2楼2023-11-05 15:06收起回复
