【图片】BMS分析3【葛立恒数二吧】

06月04日漏签0天

葛立恒数二吧关注：762贴子：64,994

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BMS分析3

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xyl
TREE
10

终于把ψ(Ω_Ω)和ψ(I)之间的BMS弄清楚了。。
这个扽的有问题吗，原谅我这丑陋的手写体

送TA礼物

IP属地:天津

来自Android客户端1楼2024-03-27 23:17回复

大概好像应该没问题

IP属地:北京

2楼2024-03-28 06:39

我扽的节点（应该是对的）
0 111 211 31 2=OFP
0 111 211 311=SIO
0 111 211 311 311=SMO
0 111 211 311 4=p(2-^w)
0 111 211 311 411=SKO
0 111 22=p(Πw)
0 111 22 311=p(real.Πω)
0 111 22 311 42=p(Π(ω2))

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3楼2024-03-28 06:47

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ndjhv
BEAF
8

强

IP属地:吉林

来自Android客户端4楼2024-03-28 07:34

膜，我到000 111 210 111就做不下去了

IP属地:安徽

来自Android客户端5楼2024-03-29 23:45

xyl
TREE
10

之后就手写分析吧，打字太麻烦还不得看
还有(0)(1,1,1)(2,1,1)(3,1)(2,1)(3,2,1)(4,2,1)(5,2)是啥啊，这段没搞懂

IP属地:天津

来自Android客户端6楼2024-03-30 09:04

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xyl
TREE
10

(0)(1,1,1)(2,1,1)(3,1)(4,2,1)(5,2,1)(6,1)(2,1)=ψ(Ω_(I2)+ψ_I(Ω_(I2))*Ω)
(0)(1,1,1)(2,1,1)(3,1)(4,2,1)(5,2,1)(6,1)(2,1)(3,2)=ψ(Ω_(I2)+ψ_I(Ω_(I2)+1))
(0)(1,1,1)(2,1,1)(3,1)(4,2,1)(5,2,1)(6,1)(2,1)(3,2,1)(4,2,1)(5,2)(4)=ψ(Ω_(I2)+ψ_I(Ω_(I2)+I))
(0)(1,1,1)(2,1,1)(3,1)(4,2,1)(5,2,1)(6,1)(2,1)(3,2,1)(4,2,1)(5,2)(6,3,1)(7,3,1)(8,2)(7)=ψ(Ω_(I2)2)
(0)(1,1,1)(2,1,1)(3,1)(4,2,1)(5,2,1)(6,1)(2,1,1)=ψ(Ω_(I2)ω)
(0)(1,1,1)(2,1,1)(3,1)(4,2,1)(5,2,1)(6,1)(2,1,1)(3,1)=ψ(Ω_(I2)*Ω)
(0)(1,1,1)(2,1,1)(3,1)(4,2,1)(5,2,1)(6,1)(2,1,1)(3,1)(2)=ψ(Ω_(I2)*I)
(0)(1,1,1)(2,1,1)(3,1)(4,2,1)(5,2,1)(6,1)(2,1,1)(3,1)(4,2)=ψ(Ω_(I2)*ψ_(I+1)(Ω_(I+1)))
(0)(1,1,1)(2,1,1)(3,1)(4,2,1)(5,2,1)(6,1)(2,1,1)(3,1)(4,2,1)(5,2,1)(6,1)(2)=ψ(Ω_(I2)*ψ_(I+1)(Ω_(I2))
(0)(1,1,1)(2,1,1)(3,1)(4,2,1)(5,2,1)(6,1)(3,1)=ψ(Ω_(I2)*ψ_(I+1)(Ω_(I2))^Ω)

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来自Android客户端7楼2024-03-31 08:25

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