费尔马大定理中n=3的证明(三)(黄振东)
作者:黄振东,
单位:利川市“龙船调”编辑部。
摘要:设x^3+y^3=z^3,可导出不成立的等式,x^3+y^3=/=z^3,
关键词:导出,不成立,等式。
Abstract: let x ^ 3 + y ^ 3 = Z ^ 3, we can derive the equation that does not hold, x ^ 3 + y ^ 3 = / = Z ^ 3,
Key words: derived, not tenable, equality.
1定理:x^3+y^3=/=z^3,(2lz))
2证明:
2,1设:x^3+y^3=z^3,
2,2:x+y三z三0(mod3),3l(x+y-z)
2,3:x^3+y^3=z^3,(x+y)(x^2-xy+y^2)=z^3,(x+y)=9m2^3,(x^2-xy+y^2)=n3^3,z=3m3*n3,(m3,n3)=1.
2,4,:z^3-y^3=x^3,(z-y)(z^2+zy+y^2)=x^2,(z-y)=m1^3(z^2+zy+y^2)=n1^3,x=m1*n1,(m1,n1)=1,
2,5:z^3-x^3=y^3.(z-x)(z^2+zx+x^2)=x^2,(z-x)=m2^3(z^2+zx+z^2)=n2^3,y=m2*n2,(m2,n2)=1,
2.6..x+y-z=(x+y)-z=x_(z-y)=y-(z-x)=3m1*m2*m3m
2,7,x^3+y^3=z^3,
x^3+3xy(x+y)+y^3=z^3+3xy^x+y).
(x+y)^3-3(x+y)z(x+y-z)-z^3=3xy^x+y)-3(x+y)z(x+y-z)-.
(x+y-z)^3=3xy^x+y)-3(x+y)z(x+y-z).
m1^2m2^2=n1n2-3m3n3m3,(1),
m1^2m2^2三1(mod3),n1n2三·2(mod3),3m3n3m3三0(mod3)
(1)式不等。
x^3+y^3=/=z^3.证毕!
作者:黄振东,
单位:利川市“龙船调”编辑部。
摘要:设x^3+y^3=z^3,可导出不成立的等式,x^3+y^3=/=z^3,
关键词:导出,不成立,等式。
Abstract: let x ^ 3 + y ^ 3 = Z ^ 3, we can derive the equation that does not hold, x ^ 3 + y ^ 3 = / = Z ^ 3,
Key words: derived, not tenable, equality.
1定理:x^3+y^3=/=z^3,(2lz))
2证明:
2,1设:x^3+y^3=z^3,
2,2:x+y三z三0(mod3),3l(x+y-z)
2,3:x^3+y^3=z^3,(x+y)(x^2-xy+y^2)=z^3,(x+y)=9m2^3,(x^2-xy+y^2)=n3^3,z=3m3*n3,(m3,n3)=1.
2,4,:z^3-y^3=x^3,(z-y)(z^2+zy+y^2)=x^2,(z-y)=m1^3(z^2+zy+y^2)=n1^3,x=m1*n1,(m1,n1)=1,
2,5:z^3-x^3=y^3.(z-x)(z^2+zx+x^2)=x^2,(z-x)=m2^3(z^2+zx+z^2)=n2^3,y=m2*n2,(m2,n2)=1,
2.6..x+y-z=(x+y)-z=x_(z-y)=y-(z-x)=3m1*m2*m3m
2,7,x^3+y^3=z^3,
x^3+3xy(x+y)+y^3=z^3+3xy^x+y).
(x+y)^3-3(x+y)z(x+y-z)-z^3=3xy^x+y)-3(x+y)z(x+y-z)-.
(x+y-z)^3=3xy^x+y)-3(x+y)z(x+y-z).
m1^2m2^2=n1n2-3m3n3m3,(1),
m1^2m2^2三1(mod3),n1n2三·2(mod3),3m3n3m3三0(mod3)
(1)式不等。
x^3+y^3=/=z^3.证毕!