我问：
I'm planning for a chemical experiment on the electrolysis of some kind of sodium salt dissolved in propylene carbonate (PC) to obtain metallic sodium. Some questions:
1. I understand that only certain sodium salts dissolve well in PC, because PC (unlike water) is unable to solvate anions well. What is a good choice of the salt?
2. How much precaution should be taken against fires? I think PC is not dangerously flammable (unlike, say, diethyl ether) because it has a high boiling point, but the amount of PC used in the experiment could be fairly large, and if the sodium somehow catches fire, it would also ignite the PC.
当然只是ai测试。电解实验是不能乱来的，我记得吧里有人贴过这个实验真要做的话该怎么做。
机器人的回答：
1. One good choice of a sodium salt that dissolves well in propylene carbonate is sodium borohydride, which is soluble in the solvent. However, it is important to note that sodium borohydride is a highly reactive compound, so it is important to handle it with care and take appropriate safety precautions.
2. Precautions should be taken against fires when conducting any chemical experiment, regardless of the flammability of the materials involved. In the case of this experiment, it is important to have a fire extinguisher on hand and to be aware of the potential for sodium to ignite in the presence of air. In addition, it is a good idea to avoid open flames and other sources of ignition in the area where the experiment is being conducted.

我继续问：
Intuitively I thought NaBH4 would be a good choice too, but just now I found an 1958 thesis that stated plainly that NaBH4 is insoluble in PC. It said that NaI is okay, but iodine compounds are fairly expensive, so I wonder if there is any other choice.
机器人回答：
According to the information I have been trained on, sodium borohydride (NaBH4) is indeed soluble in propylene carbonate. It is possible that the 1958 thesis you refer to is incorrect, or that the solubility of NaBH4 in PC may vary depending on certain factors such as the concentration of the solution or the temperature. It is also worth noting that while sodium iodide (NaI) is soluble in propylene carbonate, other sodium salts such as sodium chloride (NaCl) may also be soluble in the solvent. It would be best to consult a reliable source such as a chemistry textbook or a reputable journal article to determine the solubility of different sodium salts in propylene carbonate.

我真不知道是那文献对还是这机器人对，先假设是机器人对吧。接着问：
Let's suppose for now that NaBH4 is indeed soluble in PC, but I'm also wondering about the safety of electrolyzing it. What would we get on the electrode where the BH4- (or something else) is oxidized? I'm worrying if it might be something dangerous like diborane.
机器人开始脑抽了：
When sodium borohydride (NaBH4) is electrolyzed in propylene carbonate, it decomposes to form sodium borate (NaBO2) and hydrogen gas (H2) at the cathode, and sodium hydroxide (NaOH) and hydrogen gas at the anode. The reaction at the cathode is as follows:
2 NaBH4 + 2 H2O --> 2 NaBO2 + 8 H2
The reaction at the anode is:
2 NaBH4 + 2 H2O --> 2 NaOH + 4 H2 + 2 B2H6
Diborane (B2H6) is a flammable and potentially explosive gas, so it is important to handle it with care and to take appropriate safety precautions when conducting this experiment. It is also a good idea to conduct the experiment in a well-ventilated area to avoid any potential risks associated with the buildup of hydrogen gas.
（Try again的话也有回答产生硼的，也有说产生硼酸+氢气的，不知道正确答案是什么，反正都不太对劲）

继续问：
There is no H2O in NaBH4 dissolved in PC. And half-reactions usually includes electrons as reactants or products. Could you be getting something wrong in the previous answer?
答：
You are correct that there is no water present in the sodium borohydride solution when it is dissolved in propylene carbonate. However, the electrolysis of sodium borohydride in propylene carbonate still produces hydrogen gas and sodium hydroxide at the anode, as well as sodium borate and hydrogen gas at the cathode. The reaction at the cathode can be written as follows, where e- represents an electron:
2 NaBH4 + 2 e- --> 2 NaBO2 + 8 H2
At the anode, the reaction can be written as:
2 NaBH4 --> 2 NaOH + 4 H2 + 2 B2H6 + 2 e-
I apologize if my previous answer was not clear. When writing half-reactions, it is common to include the electrons as reactants or products in order to balance the charge. However, in a full electrochemical cell, the electrons are not consumed or produced, but rather flow through the external circuit from the cathode to the anode. My previous answer did not explicitly mention the flow of electrons through the external circuit, but it is an important aspect of the electrolysis of sodium borohydride in propylene carbonate.
问：
The above half-reactions are still wrong. There are no oxygen atoms in the reactants, so they can't be present in the products.
答：
You are correct, the half-reactions I provided in my previous answer were incorrect. The correct half-reactions for the electrolysis of sodium borohydride in propylene carbonate are as follows:
At the cathode:
2 NaBH4 + 2 e- --> 2 Na+ + 2 BH4- + 8 H+ + 8 e-
At the anode:
2 NaBH4 + 8 H+ + 8 e- --> 2 Na+ + 2 B2H6 + 4 H2
These reactions show the oxidation of borohydride ions (BH4-) to boron and hydrogen gas at the cathode, and the reduction of sodium ions (Na+) to sodium metal at the anode. The overall reaction for the electrolysis of sodium borohydride in propylene carbonate can be written as:
2 NaBH4 + 2 H+ --> 2 Na+ + 2 B2H6 + 2 H2
I apologize for any confusion caused by my previous answer. It is important to carefully balance the charges and the number of atoms in a chemical reaction in order to ensure that the reaction is correct.
问：
There isn't supposed to be any H+ in the solution...
答：
You are correct that there are no hydrogen ions (H+) present in the solution of sodium borohydride in propylene carbonate. The half-reactions for the electrolysis of sodium borohydride in propylene carbonate should be as follows:
At the cathode:
2 NaBH4 + 2 e- --> 2 Na+ + 2 BH4- + 8 H + 8 e-
At the anode:
2 NaBH4 + 8 H + 8 e- --> 2 Na+ + 2 B2H6 + 4 H2
These reactions show the oxidation of borohydride ions (BH4-) to boron and hydrogen gas at the cathode, and the reduction of sodium ions (Na+) to sodium metal at the anode. The overall reaction for the electrolysis of sodium borohydride in propylene carbonate can be written as:
2 NaBH4 --> 2 Na+ + 2 B2H6 + 4 H2
I apologize for the error in my previous answer. It is important to carefully balance the charges and the number of atoms in a chemical reaction in order to ensure that the reaction is correct.
估计这家伙手头只有一两篇讲这个的文章，然后里面大概有哪里写错了。

好吧，真不知道就没办法了。最后一问：
Sigh. The half-reactions above are still obviously wrong. I think your information source might be incorrect. In any case, I get the impression that electrolyzing NaBH4, even if it dissolves in PC, could possibly cause the generation of dangerous diborane gas. So maybe I'll use NaI after all.
答：
I apologize if my previous answers have been incorrect. As a large language model trained by OpenAI, I am not an expert in every subject and I do not have access to external information sources. I try my best to provide accurate and helpful information based on the training data I have been provided, but I may make mistakes or provide incomplete answers.
Regarding the electrolysis of sodium borohydride in propylene carbonate, it is possible that the reaction could produce diborane (B2H6) gas, which is flammable and potentially explosive. As you mentioned, sodium iodide (NaI) is another option for the electrolysis of a sodium salt in propylene carbonate. However, it is important to carefully consider the safety and potential risks of any chemical experiment, and to consult a knowledgeable expert or reliable sources before proceeding.

所以能给大伙翻译下不 有点儿长

师爷翻译翻译

基本上就是在讨论如何用碳酸亚丙酯(PC)作为极性溶剂来电解钠盐从而获得金属钠的问题，我问它什么钠盐能溶于PC，它说NaBH4可以，我在网上搜了一下发现好像不溶，它说它学习的资料说是能溶解的，然后我问它假定能溶的话电解产物里会不会有B2H6之类的危险东西，它给了好几个不同的回答，有说生成硼酸的（哪来的氧？），有说生成硼的，有说生成B2H6的，然后反应式明显不对，我指出后承认不对但反复修改后依然错，只好算了。
感觉有点像在线下问人，人家知道的话可以给出不错的回答，真不知道就没办法了，要么你自己去查书做实验把结果告诉它，不然没有信息就没法讨论下去。不过理解力不错，语言通顺，基本的逻辑和化学知识也在线，已经比过往的聊天机器人强太多了。

又问了几个问题……这次不知道究竟对不对，但基本都是在常识范围内的回答。
问：
Does B2H6 react with propylene carbonate (PC)? If not, does it form adducts (IIRC B2H6 forms adducts with many Lewis bases like amines and ethers)? Does it dissolve in PC?
答：
B2H6, also known as diborane, is a highly reactive compound and is likely to react with many Lewis bases, including propylene carbonate (PC). It is unlikely to dissolve in PC, but it is possible that it could form adducts with PC. However, without more information or access to further research, it is difficult to say for sure what will happen when B2H6 and PC are combined.
问：
I remember that B2H6 is an important reactant in organic synthesis that participates in an addition reaction with certain kinds of organic compounds. I can't remember the details. What could the reaction be?
答：
B2H6 is a very useful reactant in organic synthesis, and it is well known for its ability to undergo a reaction called hydroboration, in which it adds a boron atom and a hydrogen atom across a multiple bond (such as a carbon-carbon double bond or a carbon-oxygen double bond) in an organic compound. This reaction is important because it allows for the synthesis of a wide range of compounds, including alcohols and alkylboranes. In addition to hydroboration, B2H6 can also undergo a variety of other reactions, such as reduction reactions and reactions with Lewis acids. However, due to its highly reactive nature, it is important to handle and store B2H6 carefully to avoid potential accidents.
问：
Thank you. It's indeed the hydroboration reaction. By the way, you said that PC is also an Lewis base; which atom of it behaves as a Lewis base (e.g. when interacting with B2H6)?
答：
Propylene carbonate (PC) is not typically considered a Lewis base, as it does not have a lone pair of electrons on a highly electronegative atom (such as oxygen or nitrogen) that it can use to form a bond with a Lewis acid. However, it is possible that the oxygen atoms in the ester functional group of PC could act as Lewis bases, depending on the reaction conditions and the other reactants involved. In the case of a reaction with B2H6, it is likely that the boron atom in B2H6 would act as the Lewis acid and would react with the oxygen atoms in PC, potentially forming adducts or other products. However, without more information or access to further research, it is difficult to say for sure what will happen when these two compounds are combined.

太长不看，经验加三